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The interior lighting power allowance of a tenant space is 23,280 watts. What mi

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发表于 2012-8-4 17:13:07 |只看该作者 |倒序浏览
试卷: LEED AP ID+C 模拟试卷C[查看]
The interior lighting power allowance of a tenant space is 23,280 watts. What minimum lighting power reduction must be achieved for the project to earn 6 points?
A: 10,476 watts
B: 8,148 watts
C: 6,984 watts
D: 9,312 watts

参考答案: D

本题解释:
Reference: Energy and Atmosphere Credit, Optimize Energy Performance-Lighting Power, Calculations

To earn 6 points the project needs to achieve a 40% reduction. 5 points would be earned for Energy and Atmosphere Credit, Optimize Energy Performance-Lighting Power and 1 point for exemplary performance under ID Credit 1.

To calculate the lighting power reduction use each answer choice to determine what will yield the 40% reduction.

Percent reduction = Lighting power reduction (watts) / Interior lighting power allowance (watts)

9,312 watts / 23280 watts = 40% YES
10,476 watts / 23280 watts = 45% YES, but the question asks for the minimum reduction
8,148 watts / 23280 watts = 35% NO, earns 5 points
6,984 watts / 23280 watts = 30% NO, earns 4 points

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